What are the solutions to the equation 12(x)^2+12x=826 ?

The solutions to the equation 12(x)^2+12x=826 are x=(-3+sqrt(2487))/6 ,x=-(3+sqrt(2487))/6

Find the zeros of 12(x)^2+12x=826

The zeros of 12(x)^2+12x=826 are x=(-3+sqrt(2487))/6 ,x=-(3+sqrt(2487))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 (x)^{2} + 12 x = 826

x = \frac{- 3 + 2487}{6}, x = - \frac{3 + 2487}{6}

Decimal Notation

x = 7.81163 \dots, x = - 8.81163 \dots

Solution steps

12 x^{2} + 12 x = 826

Move

826

to the left side

12 x^{2} + 12 x - 826 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 12 ( - 826 )}{2 \cdot 12}

1 2^{2} - 4 \cdot 12 (- 826) = 42487

x_{1, 2} = \frac{- 12 \pm 4 2487}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 12 + 4 2487}{2 \cdot 12}, x_{2} = \frac{- 12 - 4 2487}{2 \cdot 12}

x = \frac{- 12 + 4 2487}{2 \cdot 12} : \frac{- 3 + 2487}{6}

x = \frac{- 12 - 4 2487}{2 \cdot 12} : - \frac{3 + 2487}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2487}{6}, x = - \frac{3 + 2487}{6}

8 x - 6 > 12 + 2 x

15 = \frac{3}{4} (9 x + 8)

∣ - 2 x + 5 ∣ \leq 15

5 4^{2}

\frac{1}{2} - \frac{3}{7}

What are the solutions to the equation 12(x)^2+12x=826 ?
The solutions to the equation 12(x)^2+12x=826 are x=(-3+sqrt(2487))/6 ,x=-(3+sqrt(2487))/6
Find the zeros of 12(x)^2+12x=826
The zeros of 12(x)^2+12x=826 are x=(-3+sqrt(2487))/6 ,x=-(3+sqrt(2487))/6