What are the solutions to the equation 9x^2-5x=4 ?

The solutions to the equation 9x^2-5x=4 are x=1,x=-4/9

Find the zeros of 9x^2-5x=4

The zeros of 9x^2-5x=4 are x=1,x=-4/9

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9 x^{2} - 5 x = 4

x = 1, x = - \frac{4}{9}

Decimal Notation

x = 1, x = - 0.44444 \dots

Solution steps

9 x^{2} - 5 x = 4

Move

4

to the left side

9 x^{2} - 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

(- 5)^{2} - 4 \cdot 9 (- 4) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 9}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 9}

x = \frac{- ( - 5 ) + 13}{2 \cdot 9} : 1

x = \frac{- ( - 5 ) - 13}{2 \cdot 9} : - \frac{4}{9}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{9}

x, y + x^{2} = 0

x, P (x - 3) = x^{2} + m x + 4

4 m^{2} + 4 m = 63

0.02 w^{2} - 0.3 w - 20 = 0

36 k^{2} + 36 k^{2} + 36 k^{2} = (243)^{2}

What are the solutions to the equation 9x^2-5x=4 ?
The solutions to the equation 9x^2-5x=4 are x=1,x=-4/9
Find the zeros of 9x^2-5x=4
The zeros of 9x^2-5x=4 are x=1,x=-4/9