What are the solutions to the equation 3x^2+2sqrt(6)x+2=0 ?

The solutions to the equation 3x^2+2sqrt(6)x+2=0 are x=-sqrt(2/3)

Find the zeros of 3x^2+2sqrt(6)x+2=0

The zeros of 3x^2+2sqrt(6)x+2=0 are x=-sqrt(2/3)

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3 x^{2} + 26 x + 2 = 0

x = - \frac{2}{3}

Decimal Notation

x = - 0.81649 \dots

Solution steps

3 x^{2} + 26 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 6 \pm ( 2 6 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(26)^{2} - 4 \cdot 3 \cdot 2 = 0

x_{1, 2} = \frac{- 2 6 \pm 0}{2 \cdot 3}

x = \frac{- 2 6}{2 \cdot 3}

\frac{- 2 6}{2 \cdot 3} = - \frac{2}{3}

x = - \frac{2}{3}

The solution to the quadratic equation is:

x = - \frac{2}{3}

4 x^{2} = - 4 x + 1

4 r^{2} - 5 r = 0

x, \frac{x ^{2}}{36} - \frac{z ^{2}}{25} = 9 y

x, x^{2} + y^{2} + 5 = 2 (x + 2 y)

(0.4) (9.8) (0.1) = \frac{200}{2} (x - 0.1)^{2}

What are the solutions to the equation 3x^2+2sqrt(6)x+2=0 ?
The solutions to the equation 3x^2+2sqrt(6)x+2=0 are x=-sqrt(2/3)
Find the zeros of 3x^2+2sqrt(6)x+2=0
The zeros of 3x^2+2sqrt(6)x+2=0 are x=-sqrt(2/3)