What are the solutions to the equation x^2-27x=-162 ?

The solutions to the equation x^2-27x=-162 are x=18,x=9

Find the zeros of x^2-27x=-162

The zeros of x^2-27x=-162 are x=18,x=9

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x^{2} - 27 x = - 162

x = 18, x = 9

Solution steps

x^{2} - 27 x = - 162

Move

162

to the left side

x^{2} - 27 x + 162 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 1 \cdot 162}{2 \cdot 1}

(- 27)^{2} - 4 \cdot 1 \cdot 162 = 9

x_{1, 2} = \frac{- ( - 27 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 27 ) - 9}{2 \cdot 1}

x = \frac{- ( - 27 ) + 9}{2 \cdot 1} : 18

x = \frac{- ( - 27 ) - 9}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

x = 18, x = 9

x^{2} + 12 x + 45

x^{2} + 6 x - 2 = 0

196 = 112 t - 16 t^{2}

x (x + 6) = 160

x^{2} = 4, 9 = 9

What are the solutions to the equation x^2-27x=-162 ?
The solutions to the equation x^2-27x=-162 are x=18,x=9
Find the zeros of x^2-27x=-162
The zeros of x^2-27x=-162 are x=18,x=9