What are the solutions to the equation y^2-2y-9=0 ?

The solutions to the equation y^2-2y-9=0 are y=1+sqrt(10),y=1-sqrt(10)

Find the zeros of y^2-2y-9=0

The zeros of y^2-2y-9=0 are y=1+sqrt(10),y=1-sqrt(10)

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y^{2} - 2 y - 9 = 0

y = 1 + 10, y = 1 - 10

Decimal Notation

y = 4.16227 \dots, y = - 2.16227 \dots

Solution steps

y^{2} - 2 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 9) = 210

y_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2 10}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2 10}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2 10}{2 \cdot 1} : 1 + 10

y = \frac{- ( - 2 ) - 2 10}{2 \cdot 1} : 1 - 10

The solutions to the quadratic equation are:

y = 1 + 10, y = 1 - 10

x^{2} = 1^{2} + 3^{2}

(M^{2} - M - 5) = 0

y (y - 3) = 4

15 x - 2 x^{2} = 27

x, f = g (x in x)

What are the solutions to the equation y^2-2y-9=0 ?
The solutions to the equation y^2-2y-9=0 are y=1+sqrt(10),y=1-sqrt(10)
Find the zeros of y^2-2y-9=0
The zeros of y^2-2y-9=0 are y=1+sqrt(10),y=1-sqrt(10)