What are the solutions to the equation factor 2x^2+10x=28 ?

The solutions to the equation factor 2x^2+10x=28 are x=2,x=-7

Find the zeros of factor 2x^2+10x=28

The zeros of factor 2x^2+10x=28 are x=2,x=-7

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2 x^{2} + 10 x = 28

x = 2, x = - 7

Solution steps

2 x^{2} + 10 x = 28

Move

28

to the left side

2 x^{2} + 10 x - 28 = 0

Factor

2 x^{2} + 10 x - 28 : 2 (x - 2) (x + 7)

2 (x - 2) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 7 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

(x + 6) (x + 2) = 60

(x - 1)^{2} + 9 = 0

0 = 100 - 4.9 t^{2}

- x^{2} + 6 x + 21 = 0

x^{2} + 0.08 = 0

What are the solutions to the equation factor 2x^2+10x=28 ?
The solutions to the equation factor 2x^2+10x=28 are x=2,x=-7
Find the zeros of factor 2x^2+10x=28
The zeros of factor 2x^2+10x=28 are x=2,x=-7