What are the solutions to the equation 3y^2+6y+5=0 ?

The solutions to the equation 3y^2+6y+5=0 are y=-1+isqrt(2/3),y=-1-isqrt(2/3)

Find the zeros of 3y^2+6y+5=0

The zeros of 3y^2+6y+5=0 are y=-1+isqrt(2/3),y=-1-isqrt(2/3)

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3 y^{2} + 6 y + 5 = 0

y = - 1 + i \frac{2}{3}, y = - 1 - i \frac{2}{3}

Solution steps

3 y^{2} + 6 y + 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 5 : 26 i

y_{1, 2} = \frac{- 6 \pm 2 6 i}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 6 + 2 6 i}{2 \cdot 3}, y_{2} = \frac{- 6 - 2 6 i}{2 \cdot 3}

y = \frac{- 6 + 2 6 i}{2 \cdot 3} : - 1 + i \frac{2}{3}

y = \frac{- 6 - 2 6 i}{2 \cdot 3} : - 1 - i \frac{2}{3}

The solutions to the quadratic equation are:

y = - 1 + i \frac{2}{3}, y = - 1 - i \frac{2}{3}

4 x^{2} + 1 = 2

x^{2} - 1.6 x + 0.64 = 0

- 7 x - 90 + 5 x^{2} = 0

x^{2} = 9 (x - 2)

a^{2} - 11 a + 18 = 0

What are the solutions to the equation 3y^2+6y+5=0 ?
The solutions to the equation 3y^2+6y+5=0 are y=-1+isqrt(2/3),y=-1-isqrt(2/3)
Find the zeros of 3y^2+6y+5=0
The zeros of 3y^2+6y+5=0 are y=-1+isqrt(2/3),y=-1-isqrt(2/3)