What are the solutions to the equation 14400=x^2-180x+20000 ?

The solutions to the equation 14400=x^2-180x+20000 are x=140,x=40

Find the zeros of 14400=x^2-180x+20000

The zeros of 14400=x^2-180x+20000 are x=140,x=40

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14400 = x^{2} - 180 x + 20000

x = 140, x = 40

Solution steps

14400 = x^{2} - 180 x + 20000

Switch sides

x^{2} - 180 x + 20000 = 14400

Move

14400

to the left side

x^{2} - 180 x + 5600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 180 ) \pm ( - 180 ) ^{2} - 4 \cdot 1 \cdot 5600}{2 \cdot 1}

(- 180)^{2} - 4 \cdot 1 \cdot 5600 = 100

x_{1, 2} = \frac{- ( - 180 ) \pm 100}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 180 ) + 100}{2 \cdot 1}, x_{2} = \frac{- ( - 180 ) - 100}{2 \cdot 1}

x = \frac{- ( - 180 ) + 100}{2 \cdot 1} : 140

x = \frac{- ( - 180 ) - 100}{2 \cdot 1} : 40

The solutions to the quadratic equation are:

x = 140, x = 40

6 x^{2} + 13 = - 11 x + 9

5 x^{2} - 60 x + 100 = 0

- 3 x^{2} - 4 x - 1 = 0

- 12 x^{2} - 8 x = 0

12 x^{2} + 4 x - 1 = 0

What are the solutions to the equation 14400=x^2-180x+20000 ?
The solutions to the equation 14400=x^2-180x+20000 are x=140,x=40
Find the zeros of 14400=x^2-180x+20000
The zeros of 14400=x^2-180x+20000 are x=140,x=40