What are the solutions to the equation 2=4x^2-5 ?

The solutions to the equation 2=4x^2-5 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

Find the zeros of 2=4x^2-5

The zeros of 2=4x^2-5 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

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2 = 4 x^{2} - 5

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 1.32287 \dots, x = - 1.32287 \dots

Solution steps

2 = 4 x^{2} - 5

Switch sides

4 x^{2} - 5 = 2

Move

5

to the right side

4 x^{2} = 7

Divide both sides by

4

x^{2} = \frac{7}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{4}, x = - \frac{7}{4}

\frac{7}{4} = \frac{7}{2}

- \frac{7}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

- 6 - c^{2} = - 23

\frac{22 \cdot x ^{2}}{2} - 8.69 \cdot 12.6 \cdot (35.9 - x) = 0

- 3 x^{2} - 7 x + 7 = x^{2} + 2 x + 9

0.43 = - 2 \cdot + 1 0^{- 6} x^{2} + 0.0011 x + 0.3548

8 x^{2} - 169 = 0

What are the solutions to the equation 2=4x^2-5 ?
The solutions to the equation 2=4x^2-5 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2
Find the zeros of 2=4x^2-5
The zeros of 2=4x^2-5 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2