What are the solutions to the equation 12x^2-5x+2=0 ?

The solutions to the equation 12x^2-5x+2=0 are x= 5/24+i(sqrt(71))/(24),x= 5/24-i(sqrt(71))/(24)

Find the zeros of 12x^2-5x+2=0

The zeros of 12x^2-5x+2=0 are x= 5/24+i(sqrt(71))/(24),x= 5/24-i(sqrt(71))/(24)

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12 x^{2} - 5 x + 2 = 0

x = \frac{5}{24} + i \frac{71}{24}, x = \frac{5}{24} - i \frac{71}{24}

Solution steps

12 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 12 \cdot 2}{2 \cdot 12}

Simplify

(- 5)^{2} - 4 \cdot 12 \cdot 2 : 71 i

x_{1, 2} = \frac{- ( - 5 ) \pm 71 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 71 i}{2 \cdot 12}, x_{2} = \frac{- ( - 5 ) - 71 i}{2 \cdot 12}

x = \frac{- ( - 5 ) + 71 i}{2 \cdot 12} : \frac{5}{24} + i \frac{71}{24}

x = \frac{- ( - 5 ) - 71 i}{2 \cdot 12} : \frac{5}{24} - i \frac{71}{24}

The solutions to the quadratic equation are:

x = \frac{5}{24} + i \frac{71}{24}, x = \frac{5}{24} - i \frac{71}{24}

80 = x (\frac{x}{10} - 3) - 5 (\frac{x}{10} - 3)^{2}

x, 4 x^{2} - 12 x + 9 = 0

10700 x^{2} + 5000 x + 3500 = 0

(x - 5) (x + 5) = (x - 1)

x^{2} + 2 x + 13 = - 8

What are the solutions to the equation 12x^2-5x+2=0 ?
The solutions to the equation 12x^2-5x+2=0 are x= 5/24+i(sqrt(71))/(24),x= 5/24-i(sqrt(71))/(24)
Find the zeros of 12x^2-5x+2=0
The zeros of 12x^2-5x+2=0 are x= 5/24+i(sqrt(71))/(24),x= 5/24-i(sqrt(71))/(24)