What are the solutions to the equation x^2+6x+19=-6 ?

The solutions to the equation x^2+6x+19=-6 are x=-3+4i,x=-3-4i

Find the zeros of x^2+6x+19=-6

The zeros of x^2+6x+19=-6 are x=-3+4i,x=-3-4i

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x^{2} + 6 x + 19 = - 6

x = - 3 + 4 i, x = - 3 - 4 i

Solution steps

x^{2} + 6 x + 19 = - 6

Move

6

to the left side

x^{2} + 6 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 25 : 8 i

x_{1, 2} = \frac{- 6 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 8 i}{2 \cdot 1}

x = \frac{- 6 + 8 i}{2 \cdot 1} : - 3 + 4 i

x = \frac{- 6 - 8 i}{2 \cdot 1} : - 3 - 4 i

The solutions to the quadratic equation are:

x = - 3 + 4 i, x = - 3 - 4 i

(m - 10)^{2} = - 20 m

0 = - \frac{4}{9} (x + 2)^{2} + 2

q^{2} + 8 q + 20 = 100 - 4 q - q^{2}

3 x^{2} + 3 x = 18

\frac{x ^{2}}{9} + \frac{( 2 x + 1 ) ^{2}}{4} = 1

What are the solutions to the equation x^2+6x+19=-6 ?
The solutions to the equation x^2+6x+19=-6 are x=-3+4i,x=-3-4i
Find the zeros of x^2+6x+19=-6
The zeros of x^2+6x+19=-6 are x=-3+4i,x=-3-4i