What are the solutions to the equation -8t+21=-t^2 ?

The solutions to the equation -8t+21=-t^2 are t=4-sqrt(5)i,t=4+sqrt(5)i

Find the zeros of -8t+21=-t^2

The zeros of -8t+21=-t^2 are t=4-sqrt(5)i,t=4+sqrt(5)i

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- 8 t + 21 = - t^{2}

t = 4 - 5 i, t = 4 + 5 i

Solution steps

- 8 t + 21 = - t^{2}

Switch sides

- t^{2} = - 8 t + 21

Move

21

to the left side

- t^{2} - 21 = - 8 t

Move

8 t

to the left side

- t^{2} - 21 + 8 t = 0

Write in the standard form

a x^{2} + b x + c = 0

- t^{2} + 8 t - 21 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 21 )}{2 ( - 1 )}

Simplify

8^{2} - 4 (- 1) (- 21) : 25 i

t_{1, 2} = \frac{- 8 \pm 2 5 i}{2 ( - 1 )}

Separate the solutions

t_{1} = \frac{- 8 + 2 5 i}{2 ( - 1 )}, t_{2} = \frac{- 8 - 2 5 i}{2 ( - 1 )}

t = \frac{- 8 + 2 5 i}{2 ( - 1 )} : 4 - 5 i

t = \frac{- 8 - 2 5 i}{2 ( - 1 )} : 4 + 5 i

The solutions to the quadratic equation are:

t = 4 - 5 i, t = 4 + 5 i

m^{4} - 13 m^{2} + 36

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(5^{4})^{2}

\frac{x + 1}{3} - \frac{x}{6} = \frac{2 x - 3}{2}

- 76 x + 76 = - 76 x + 76

What are the solutions to the equation -8t+21=-t^2 ?
The solutions to the equation -8t+21=-t^2 are t=4-sqrt(5)i,t=4+sqrt(5)i
Find the zeros of -8t+21=-t^2
The zeros of -8t+21=-t^2 are t=4-sqrt(5)i,t=4+sqrt(5)i