What are the solutions to the equation -3l^2+20l+100=0 ?

The solutions to the equation -3l^2+20l+100=0 are l=-10/3 ,l=10

Find the zeros of -3l^2+20l+100=0

The zeros of -3l^2+20l+100=0 are l=-10/3 ,l=10

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- 3 l^{2} + 20 l + 100 = 0

l = - \frac{10}{3}, l = 10

Decimal

l = - 3.33333 \dots, l = 10

Solution steps

- 3 l^{2} + 20 l + 100 = 0

Solve with the quadratic formula

l_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 3 ) \cdot 100}{2 ( - 3 )}

2 0^{2} - 4 (- 3) \cdot 100 = 40

l_{1, 2} = \frac{- 20 \pm 40}{2 ( - 3 )}

Separate the solutions

l_{1} = \frac{- 20 + 40}{2 ( - 3 )}, l_{2} = \frac{- 20 - 40}{2 ( - 3 )}

l = \frac{- 20 + 40}{2 ( - 3 )} : - \frac{10}{3}

l = \frac{- 20 - 40}{2 ( - 3 )} : 10

The solutions to the quadratic equation are:

l = - \frac{10}{3}, l = 10

3 (x^{2} - 2 x) = 8 (x - 2) + 8

x^{2} - 11 x - 350 = 0

x, x^{2} + y^{2} = 6 x y

0. 5^{2} + 0. 5^{2} = x^{2}

x, P_{2} (x) = 1 - \frac{1}{2} x^{2}

What are the solutions to the equation -3l^2+20l+100=0 ?
The solutions to the equation -3l^2+20l+100=0 are l=-10/3 ,l=10
Find the zeros of -3l^2+20l+100=0
The zeros of -3l^2+20l+100=0 are l=-10/3 ,l=10