What are the solutions to the equation 12x^2+6x+6=0 ?

The solutions to the equation 12x^2+6x+6=0 are x=-1/4+i(sqrt(7))/4 ,x=-1/4-i(sqrt(7))/4

Find the zeros of 12x^2+6x+6=0

The zeros of 12x^2+6x+6=0 are x=-1/4+i(sqrt(7))/4 ,x=-1/4-i(sqrt(7))/4

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12 x^{2} + 6 x + 6 = 0

x = - \frac{1}{4} + i \frac{7}{4}, x = - \frac{1}{4} - i \frac{7}{4}

Solution steps

12 x^{2} + 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 12 \cdot 6}{2 \cdot 12}

Simplify

6^{2} - 4 \cdot 12 \cdot 6 : 67 i

x_{1, 2} = \frac{- 6 \pm 6 7 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 6 + 6 7 i}{2 \cdot 12}, x_{2} = \frac{- 6 - 6 7 i}{2 \cdot 12}

x = \frac{- 6 + 6 7 i}{2 \cdot 12} : - \frac{1}{4} + i \frac{7}{4}

x = \frac{- 6 - 6 7 i}{2 \cdot 12} : - \frac{1}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{7}{4}, x = - \frac{1}{4} - i \frac{7}{4}

(x + m)^{2} = n

0 = x^{2} - 3 x + 6

180 = x (3 + x)

x, f^{- 1} (x) = x^{2} + 4

x, f^{- 1} (x) = x^{2} - 1

What are the solutions to the equation 12x^2+6x+6=0 ?
The solutions to the equation 12x^2+6x+6=0 are x=-1/4+i(sqrt(7))/4 ,x=-1/4-i(sqrt(7))/4
Find the zeros of 12x^2+6x+6=0
The zeros of 12x^2+6x+6=0 are x=-1/4+i(sqrt(7))/4 ,x=-1/4-i(sqrt(7))/4