What are the solutions to the equation completesquare x^2+3x+2=0 ?

The solutions to the equation completesquare x^2+3x+2=0 are x=-1,x=-2

Find the zeros of completesquare x^2+3x+2=0

The zeros of completesquare x^2+3x+2=0 are x=-1,x=-2

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x^{2} + 3 x + 2 = 0

x = - 1, x = - 2

Solution steps

x^{2} + 3 x + 2 = 0

Move

2

to the right side

x^{2} + 3 x = - 2

Rewrite in the form

(x + a)^{2} = b

(x + \frac{3}{2})^{2} = \frac{1}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{3}{2} = \frac{1}{4} : x = - 1

Solve

x + \frac{3}{2} = - \frac{1}{4} : x = - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

4 - d \cdot [4 - d + d] \cdot [4 - d + 2 d] = 16

x, m^{2} x^{2} + y^{2} = b^{2}

x, x^{2} + y^{2} - 2 (2 x + 3 y) + 14 = 0

- (x - 3) = (x - \frac{7}{2}) (x + \frac{3}{4})

4 x^{2} - 13 x - 35 = 0

What are the solutions to the equation completesquare x^2+3x+2=0 ?
The solutions to the equation completesquare x^2+3x+2=0 are x=-1,x=-2
Find the zeros of completesquare x^2+3x+2=0
The zeros of completesquare x^2+3x+2=0 are x=-1,x=-2