What are the solutions to the equation 7x^2-5x+6=-8 ?

The solutions to the equation 7x^2-5x+6=-8 are x= 5/14+i(sqrt(367))/(14),x= 5/14-i(sqrt(367))/(14)

Find the zeros of 7x^2-5x+6=-8

The zeros of 7x^2-5x+6=-8 are x= 5/14+i(sqrt(367))/(14),x= 5/14-i(sqrt(367))/(14)

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7 x^{2} - 5 x + 6 = - 8

x = \frac{5}{14} + i \frac{367}{14}, x = \frac{5}{14} - i \frac{367}{14}

Solution steps

7 x^{2} - 5 x + 6 = - 8

Move

8

to the left side

7 x^{2} - 5 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 7 \cdot 14}{2 \cdot 7}

Simplify

(- 5)^{2} - 4 \cdot 7 \cdot 14 : 367 i

x_{1, 2} = \frac{- ( - 5 ) \pm 367 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 367 i}{2 \cdot 7}, x_{2} = \frac{- ( - 5 ) - 367 i}{2 \cdot 7}

x = \frac{- ( - 5 ) + 367 i}{2 \cdot 7} : \frac{5}{14} + i \frac{367}{14}

x = \frac{- ( - 5 ) - 367 i}{2 \cdot 7} : \frac{5}{14} - i \frac{367}{14}

The solutions to the quadratic equation are:

x = \frac{5}{14} + i \frac{367}{14}, x = \frac{5}{14} - i \frac{367}{14}

x^{2} + x = 0.75

2^{2} + y^{2} - 6 y - 16 = 0

- x^{2} = 81

3 u^{2} = 30 u - 12

2 x^{2} + 3 = 35

What are the solutions to the equation 7x^2-5x+6=-8 ?
The solutions to the equation 7x^2-5x+6=-8 are x= 5/14+i(sqrt(367))/(14),x= 5/14-i(sqrt(367))/(14)
Find the zeros of 7x^2-5x+6=-8
The zeros of 7x^2-5x+6=-8 are x= 5/14+i(sqrt(367))/(14),x= 5/14-i(sqrt(367))/(14)