What are the solutions to the equation 0=1-3x^2 ?

The solutions to the equation 0=1-3x^2 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

Find the zeros of 0=1-3x^2

The zeros of 0=1-3x^2 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

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0 = 1 - 3 x^{2}

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.57735 \dots, x = - 0.57735 \dots

Solution steps

0 = 1 - 3 x^{2}

Switch sides

1 - 3 x^{2} = 0

Move

1

to the right side

- 3 x^{2} = - 1

Divide both sides by

- 3

x^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{3}, x = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

x^{2} - 37 = 188

2 k^{2} + 5 k + 3 = 0

\frac{5 - x}{6000} = \frac{1}{2} \cdot 0.001 \cdot (x - 1)^{2}

2 x^{2} + 11 = x^{2} + 12

\frac{1}{3} x^{2} - \frac{123}{4} x + \frac{1}{6} = 0

What are the solutions to the equation 0=1-3x^2 ?
The solutions to the equation 0=1-3x^2 are x= 1/(sqrt(3)),x=-1/(sqrt(3))
Find the zeros of 0=1-3x^2
The zeros of 0=1-3x^2 are x= 1/(sqrt(3)),x=-1/(sqrt(3))