What are the solutions to the equation 2x^2+13x-32=0 ?

The solutions to the equation 2x^2+13x-32=0 are x=(-13+5sqrt(17))/4 ,x=(-13-5sqrt(17))/4

Find the zeros of 2x^2+13x-32=0

The zeros of 2x^2+13x-32=0 are x=(-13+5sqrt(17))/4 ,x=(-13-5sqrt(17))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 13 x - 32 = 0

x = \frac{- 13 + 5 17}{4}, x = \frac{- 13 - 5 17}{4}

Decimal

x = 1.90388 \dots, x = - 8.40388 \dots

Solution steps

2 x^{2} + 13 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 32 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 32) = 517

x_{1, 2} = \frac{- 13 \pm 5 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 5 17}{2 \cdot 2}, x_{2} = \frac{- 13 - 5 17}{2 \cdot 2}

x = \frac{- 13 + 5 17}{2 \cdot 2} : \frac{- 13 + 5 17}{4}

x = \frac{- 13 - 5 17}{2 \cdot 2} : \frac{- 13 - 5 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 13 + 5 17}{4}, x = \frac{- 13 - 5 17}{4}

0.233 = - 6 (1 0^{- 5}) x^{2} + 0.0132 x

x = - 0.00075 (5 - 15 + 3 - x \cdot 100)^{2}

16 x - 32 = 9 x^{2} + 18 x + 9

10 0^{2} = (\frac{16}{9} \cdot h)^{2} + h^{2}

- 3 a = a^{2} + 2

What are the solutions to the equation 2x^2+13x-32=0 ?
The solutions to the equation 2x^2+13x-32=0 are x=(-13+5sqrt(17))/4 ,x=(-13-5sqrt(17))/4
Find the zeros of 2x^2+13x-32=0
The zeros of 2x^2+13x-32=0 are x=(-13+5sqrt(17))/4 ,x=(-13-5sqrt(17))/4