What are the solutions to the equation p^2-6p=0 ?

The solutions to the equation p^2-6p=0 are p=6,p=0

Find the zeros of p^2-6p=0

The zeros of p^2-6p=0 are p=6,p=0

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p^{2} - 6 p = 0

p = 6, p = 0

Solution steps

p^{2} - 6 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

p_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, p_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

p = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

p = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 6, p = 0

y, 25 X^{2} + 9 y^{2} = 225

55464.96 x^{2} + 95.99 x + 1 = 0

(x - 7) (x + 3) = 24

x^{2} + 9 x = - 20

c^{2} = 81

What are the solutions to the equation p^2-6p=0 ?
The solutions to the equation p^2-6p=0 are p=6,p=0
Find the zeros of p^2-6p=0
The zeros of p^2-6p=0 are p=6,p=0