What are the solutions to the equation λ^2-7λ+10=0 ?

The solutions to the equation λ^2-7λ+10=0 are λ=5,λ=2

Find the zeros of λ^2-7λ+10=0

The zeros of λ^2-7λ+10=0 are λ=5,λ=2

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λ^{2} - 7 λ + 10 = 0

λ = 5, λ = 2

Solution steps

λ^{2} - 7 λ + 10 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

λ_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, λ_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

λ = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

λ = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

λ = 5, λ = 2

(11 x - 18) (6 x + 10) = 0

3 x^{2} - 40 x + 20000 = 0

y, x = y^{2} - 4 y + 3

(8 x + 9)^{2} = 4

x, x^{2} + y^{2} + 6 = 0

What are the solutions to the equation λ^2-7λ+10=0 ?
The solutions to the equation λ^2-7λ+10=0 are λ=5,λ=2
Find the zeros of λ^2-7λ+10=0
The zeros of λ^2-7λ+10=0 are λ=5,λ=2