What are the solutions to the equation 7x^2+29x+4=0 ?

The solutions to the equation 7x^2+29x+4=0 are x=-1/7 ,x=-4

Find the zeros of 7x^2+29x+4=0

The zeros of 7x^2+29x+4=0 are x=-1/7 ,x=-4

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7 x^{2} + 29 x + 4 = 0

x = - \frac{1}{7}, x = - 4

Decimal Notation

x = - 0.14285 \dots, x = - 4

Solution steps

7 x^{2} + 29 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 \cdot 7 \cdot 4}{2 \cdot 7}

2 9^{2} - 4 \cdot 7 \cdot 4 = 27

x_{1, 2} = \frac{- 29 \pm 27}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 29 + 27}{2 \cdot 7}, x_{2} = \frac{- 29 - 27}{2 \cdot 7}

x = \frac{- 29 + 27}{2 \cdot 7} : - \frac{1}{7}

x = \frac{- 29 - 27}{2 \cdot 7} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{7}, x = - 4

x^{2} - 2 x - 27 = 0

2 x^{2} + 10 x + 25 = 0

x^{2} + 4 x - 40 = 10 x + 15

1^{2} + y^{2} = 2^{2}

x^{2} + (2 x + 3)^{2} = 24

What are the solutions to the equation 7x^2+29x+4=0 ?
The solutions to the equation 7x^2+29x+4=0 are x=-1/7 ,x=-4
Find the zeros of 7x^2+29x+4=0
The zeros of 7x^2+29x+4=0 are x=-1/7 ,x=-4