What are the solutions to the equation 12x^2+32x-64=0 ?

The solutions to the equation 12x^2+32x-64=0 are x= 4/3 ,x=-4

Find the zeros of 12x^2+32x-64=0

The zeros of 12x^2+32x-64=0 are x= 4/3 ,x=-4

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12 x^{2} + 32 x - 64 = 0

x = \frac{4}{3}, x = - 4

Decimal Notation

x = 1.33333 \dots, x = - 4

Solution steps

12 x^{2} + 32 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 12 ( - 64 )}{2 \cdot 12}

3 2^{2} - 4 \cdot 12 (- 64) = 64

x_{1, 2} = \frac{- 32 \pm 64}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 32 + 64}{2 \cdot 12}, x_{2} = \frac{- 32 - 64}{2 \cdot 12}

x = \frac{- 32 + 64}{2 \cdot 12} : \frac{4}{3}

x = \frac{- 32 - 64}{2 \cdot 12} : - 4

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 4

8 - t^{2} = 0

t^{2} - 9 t + 20 = 0

0 = 3 x^{2} - 6 x + 7

1600 = 2 y^{2}

1 - 4 x - 4 x^{2} = 0

What are the solutions to the equation 12x^2+32x-64=0 ?
The solutions to the equation 12x^2+32x-64=0 are x= 4/3 ,x=-4
Find the zeros of 12x^2+32x-64=0
The zeros of 12x^2+32x-64=0 are x= 4/3 ,x=-4