What are the solutions to the equation x^2-200x+9900=0 ?

The solutions to the equation x^2-200x+9900=0 are x=110,x=90

Find the zeros of x^2-200x+9900=0

The zeros of x^2-200x+9900=0 are x=110,x=90

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x^{2} - 200 x + 9900 = 0

x = 110, x = 90

Solution steps

x^{2} - 200 x + 9900 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 1 \cdot 9900}{2 \cdot 1}

(- 200)^{2} - 4 \cdot 1 \cdot 9900 = 20

x_{1, 2} = \frac{- ( - 200 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 200 ) - 20}{2 \cdot 1}

x = \frac{- ( - 200 ) + 20}{2 \cdot 1} : 110

x = \frac{- ( - 200 ) - 20}{2 \cdot 1} : 90

The solutions to the quadratic equation are:

x = 110, x = 90

s^{2} + s - 1 = 0

- 1 = x^{2} + 2 x

- x^{2} + 18 x - 80 = 0

4 8^{2} + x^{2} = 7 3^{2}

4 x^{2} + x + 5 = 9 x + 2

What are the solutions to the equation x^2-200x+9900=0 ?
The solutions to the equation x^2-200x+9900=0 are x=110,x=90
Find the zeros of x^2-200x+9900=0
The zeros of x^2-200x+9900=0 are x=110,x=90