What are the solutions to the equation 3(x-4)(x-2)+(x-1)^2=0 ?

The solutions to the equation 3(x-4)(x-2)+(x-1)^2=0 are x= 5/2

Find the zeros of 3(x-4)(x-2)+(x-1)^2=0

The zeros of 3(x-4)(x-2)+(x-1)^2=0 are x= 5/2

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3 (x - 4) (x - 2) + (x - 1)^{2} = 0

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

3 (x - 4) (x - 2) + (x - 1)^{2} = 0

Expand

3 (x - 4) (x - 2) + (x - 1)^{2} : 4 x^{2} - 20 x + 25

4 x^{2} - 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

12 x^{2} - 10 x - 12 = 0

3 x^{2} + 6 x - 5 = 4

(b + 7)^{2} = 0

x, 2 x^{2} - k x + 4 = 0

5 x^{2} = 315

What are the solutions to the equation 3(x-4)(x-2)+(x-1)^2=0 ?
The solutions to the equation 3(x-4)(x-2)+(x-1)^2=0 are x= 5/2
Find the zeros of 3(x-4)(x-2)+(x-1)^2=0
The zeros of 3(x-4)(x-2)+(x-1)^2=0 are x= 5/2