What are the solutions to the equation x(x+1)=2070 ?

The solutions to the equation x(x+1)=2070 are x=45,x=-46

Find the zeros of x(x+1)=2070

The zeros of x(x+1)=2070 are x=45,x=-46

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x (x + 1) = 2070

x = 45, x = - 46

Solution steps

x (x + 1) = 2070

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 2070

Move

2070

to the left side

x^{2} + x - 2070 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2070 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2070) = 91

x_{1, 2} = \frac{- 1 \pm 91}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 91}{2 \cdot 1}, x_{2} = \frac{- 1 - 91}{2 \cdot 1}

x = \frac{- 1 + 91}{2 \cdot 1} : 45

x = \frac{- 1 - 91}{2 \cdot 1} : - 46

The solutions to the quadratic equation are:

x = 45, x = - 46

\frac{1}{6} x + 6 + 2 < 3

2 x^{4} - 5 x^{2} - 3

2 y^{2} + 1 = 6 y

(\frac{2}{3})^{1}

\frac{x + 6}{x - 6} < 0

What are the solutions to the equation x(x+1)=2070 ?
The solutions to the equation x(x+1)=2070 are x=45,x=-46
Find the zeros of x(x+1)=2070
The zeros of x(x+1)=2070 are x=45,x=-46