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Popular >

b^2-13b+40=0

Solution

b^{2} - 13 b + 40 = 0

Solution

b = 8, b = 5

Solution steps

b^{2} - 13 b + 40 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 40 = 3

b_{1, 2} = \frac{- ( - 13 ) \pm 3}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 13 ) + 3}{2 \cdot 1}, b_{2} = \frac{- ( - 13 ) - 3}{2 \cdot 1}

b = \frac{- ( - 13 ) + 3}{2 \cdot 1} : 8

b = \frac{- ( - 13 ) - 3}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

b = 8, b = 5

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(x - 3) (x + 1) + 4 = 0

x^2+(-1)x+(-1)+8=0

x^{2} + (- 1) x + (- 1) + 8 = 0

c=(2x-3)(2x-2)-2x(x-5)

c = (2 x - 3) (2 x - 2) - 2 x (x - 5)

Frequently Asked Questions (FAQ)

What are the solutions to the equation b^2-13b+40=0 ?
The solutions to the equation b^2-13b+40=0 are b=8,b=5
Find the zeros of b^2-13b+40=0
The zeros of b^2-13b+40=0 are b=8,b=5