What are the solutions to the equation (3x-2)^2=7 ?

The solutions to the equation (3x-2)^2=7 are x=(sqrt(7)+2)/3 ,x=(-sqrt(7)+2)/3

Find the zeros of (3x-2)^2=7

The zeros of (3x-2)^2=7 are x=(sqrt(7)+2)/3 ,x=(-sqrt(7)+2)/3

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(3 x - 2)^{2} = 7

x = \frac{7 + 2}{3}, x = \frac{- 7 + 2}{3}

Decimal Notation

x = 1.54858 \dots, x = - 0.21525 \dots

Solution steps

(3 x - 2)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 2 = 7 : x = \frac{7 + 2}{3}

Solve

3 x - 2 = - 7 : x = \frac{- 7 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 2}{3}, x = \frac{- 7 + 2}{3}

5 x^{2} + 6 = 6

(4 x + 7)^{2} = (7 x + 4)^{2}

2 x^{2} - 16 x + 24 = 0

X^{1} + X^{2} = 103

x^{2} + 8 x + 52

What are the solutions to the equation (3x-2)^2=7 ?
The solutions to the equation (3x-2)^2=7 are x=(sqrt(7)+2)/3 ,x=(-sqrt(7)+2)/3
Find the zeros of (3x-2)^2=7
The zeros of (3x-2)^2=7 are x=(sqrt(7)+2)/3 ,x=(-sqrt(7)+2)/3