What are the solutions to the equation solvefor t,r(t)=300t-300t^2 ?

The solutions to the equation solvefor t,r(t)=300t-300t^2 are t=0,t=(300-r)/(300)

Find the zeros of solvefor t,r(t)=300t-300t^2

The zeros of solvefor t,r(t)=300t-300t^2 are t=0,t=(300-r)/(300)

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solve for

t, r (t) = 300 t - 300 t^{2}

t = 0, t = \frac{300 - r}{300}

Solution steps

r (t) = 300 t - 300 t^{2}

Refine

t r = 300 t - 300 t^{2}

Switch sides

300 t - 300 t^{2} = t r

Move

t r

to the left side

300 t - 300 t^{2} - t r = 0

Write in the standard form

a x^{2} + b x + c = 0

- 300 t^{2} + (300 - r) t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( 300 - r ) \pm ( 300 - r ) ^{2} - 4 ( - 300 ) \cdot 0}{2 ( - 300 )}

Simplify

(300 - r)^{2} - 4 (- 300) \cdot 0 : - r + 300

t_{1, 2} = \frac{- ( 300 - r ) \pm ( - r + 300 )}{2 ( - 300 )}

Separate the solutions

t_{1} = \frac{- ( 300 - r ) - r + 300}{2 ( - 300 )}, t_{2} = \frac{- ( 300 - r ) - ( - r + 300 )}{2 ( - 300 )}

t = \frac{- ( 300 - r ) - r + 300}{2 ( - 300 )} : 0

t = \frac{- ( 300 - r ) - ( - r + 300 )}{2 ( - 300 )} : \frac{300 - r}{300}

The solutions to the quadratic equation are:

t = 0, t = \frac{300 - r}{300}

1 7^{2} = x^{2} + (x + 7)^{2}

t, t^{2} + 12 t + a = 0

x^{2} - 11 x + 25 = 0

4 h^{2} = 3 l^{2}

x, z = x^{2} y - x + y + 1

What are the solutions to the equation solvefor t,r(t)=300t-300t^2 ?
The solutions to the equation solvefor t,r(t)=300t-300t^2 are t=0,t=(300-r)/(300)
Find the zeros of solvefor t,r(t)=300t-300t^2
The zeros of solvefor t,r(t)=300t-300t^2 are t=0,t=(300-r)/(300)