What are the solutions to the equation 8t^2+10t+5=0 ?

The solutions to the equation 8t^2+10t+5=0 are t=-5/8+i(sqrt(15))/8 ,t=-5/8-i(sqrt(15))/8

Find the zeros of 8t^2+10t+5=0

The zeros of 8t^2+10t+5=0 are t=-5/8+i(sqrt(15))/8 ,t=-5/8-i(sqrt(15))/8

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8 t^{2} + 10 t + 5 = 0

t = - \frac{5}{8} + i \frac{15}{8}, t = - \frac{5}{8} - i \frac{15}{8}

Solution steps

8 t^{2} + 10 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

Simplify

1 0^{2} - 4 \cdot 8 \cdot 5 : 215 i

t_{1, 2} = \frac{- 10 \pm 2 15 i}{2 \cdot 8}

Separate the solutions

t_{1} = \frac{- 10 + 2 15 i}{2 \cdot 8}, t_{2} = \frac{- 10 - 2 15 i}{2 \cdot 8}

t = \frac{- 10 + 2 15 i}{2 \cdot 8} : - \frac{5}{8} + i \frac{15}{8}

t = \frac{- 10 - 2 15 i}{2 \cdot 8} : - \frac{5}{8} - i \frac{15}{8}

The solutions to the quadratic equation are:

t = - \frac{5}{8} + i \frac{15}{8}, t = - \frac{5}{8} - i \frac{15}{8}

x + 5 = - 2 x^{2} + x + 1

5 y^{2} + 8 y - 100 = y^{2} + 4 y - 37

x, x^{2} + 4 x y + y^{2} = 5

x^{2} + 3 + 2 = 0

x, 2 x^{2} - 8 x y - y^{2} - x + 3 y + 6 = 0

What are the solutions to the equation 8t^2+10t+5=0 ?
The solutions to the equation 8t^2+10t+5=0 are t=-5/8+i(sqrt(15))/8 ,t=-5/8-i(sqrt(15))/8
Find the zeros of 8t^2+10t+5=0
The zeros of 8t^2+10t+5=0 are t=-5/8+i(sqrt(15))/8 ,t=-5/8-i(sqrt(15))/8