What are the solutions to the equation -3x^2+8=2x ?

The solutions to the equation -3x^2+8=2x are x=-2,x= 4/3

Find the zeros of -3x^2+8=2x

The zeros of -3x^2+8=2x are x=-2,x= 4/3

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- 3 x^{2} + 8 = 2 x

x = - 2, x = \frac{4}{3}

Decimal Notation

x = - 2, x = 1.33333 \dots

Solution steps

- 3 x^{2} + 8 = 2 x

Move

2 x

to the left side

- 3 x^{2} + 8 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} - 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

(- 2)^{2} - 4 (- 3) \cdot 8 = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 10}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 10}{2 ( - 3 )} : - 2

x = \frac{- ( - 2 ) - 10}{2 ( - 3 )} : \frac{4}{3}

The solutions to the quadratic equation are:

x = - 2, x = \frac{4}{3}

5 x^{2} + 0 x + 0 = 0

- 16 x^{2} + 8 x - 1 = 0

30 = x^{2} (0.3)

3 x^{2} - 2 = 11 x

\frac{4}{3} x^{2} = 1

What are the solutions to the equation -3x^2+8=2x ?
The solutions to the equation -3x^2+8=2x are x=-2,x= 4/3
Find the zeros of -3x^2+8=2x
The zeros of -3x^2+8=2x are x=-2,x= 4/3