What are the solutions to the equation 8x^2+3x=-7 ?

The solutions to the equation 8x^2+3x=-7 are x=-3/16+i(sqrt(215))/(16),x=-3/16-i(sqrt(215))/(16)

Find the zeros of 8x^2+3x=-7

The zeros of 8x^2+3x=-7 are x=-3/16+i(sqrt(215))/(16),x=-3/16-i(sqrt(215))/(16)

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8 x^{2} + 3 x = - 7

x = - \frac{3}{16} + i \frac{215}{16}, x = - \frac{3}{16} - i \frac{215}{16}

Solution steps

8 x^{2} + 3 x = - 7

Move

7

to the left side

8 x^{2} + 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 8 \cdot 7}{2 \cdot 8}

Simplify

3^{2} - 4 \cdot 8 \cdot 7 : 215 i

x_{1, 2} = \frac{- 3 \pm 215 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 3 + 215 i}{2 \cdot 8}, x_{2} = \frac{- 3 - 215 i}{2 \cdot 8}

x = \frac{- 3 + 215 i}{2 \cdot 8} : - \frac{3}{16} + i \frac{215}{16}

x = \frac{- 3 - 215 i}{2 \cdot 8} : - \frac{3}{16} - i \frac{215}{16}

The solutions to the quadratic equation are:

x = - \frac{3}{16} + i \frac{215}{16}, x = - \frac{3}{16} - i \frac{215}{16}

x^{2} = 0.81

x^{2} - 42 x + n = 0

\frac{1}{2} x^{2} - \frac{1}{4} x = 0

1 - (\frac{( 1 - 5 )}{2} x)^{2} - x^{2} = 0

- \frac{3}{2} x^{2} - 12 x + 54 = 0

What are the solutions to the equation 8x^2+3x=-7 ?
The solutions to the equation 8x^2+3x=-7 are x=-3/16+i(sqrt(215))/(16),x=-3/16-i(sqrt(215))/(16)
Find the zeros of 8x^2+3x=-7
The zeros of 8x^2+3x=-7 are x=-3/16+i(sqrt(215))/(16),x=-3/16-i(sqrt(215))/(16)