What are the solutions to the equation 3x^2-25x+8=0 ?

The solutions to the equation 3x^2-25x+8=0 are x=8,x= 1/3

Find the zeros of 3x^2-25x+8=0

The zeros of 3x^2-25x+8=0 are x=8,x= 1/3

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3 x^{2} - 25 x + 8 = 0

x = 8, x = \frac{1}{3}

Decimal Notation

x = 8, x = 0.33333 \dots

Solution steps

3 x^{2} - 25 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

(- 25)^{2} - 4 \cdot 3 \cdot 8 = 23

x_{1, 2} = \frac{- ( - 25 ) \pm 23}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 23}{2 \cdot 3}, x_{2} = \frac{- ( - 25 ) - 23}{2 \cdot 3}

x = \frac{- ( - 25 ) + 23}{2 \cdot 3} : 8

x = \frac{- ( - 25 ) - 23}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 8, x = \frac{1}{3}

x^{2} - 24 = 120

2 x^{2} + (6 \cdot 1 0^{- 5}) x - (7.2 \cdot 1 0^{- 9}) = 0

A, A XB = (B A)^{2}

- 2 (x - \frac{1}{2})^{2} + 8 = - 2 x + \frac{3}{2}

5 x^{2} + 8 x - 6 = 0

What are the solutions to the equation 3x^2-25x+8=0 ?
The solutions to the equation 3x^2-25x+8=0 are x=8,x= 1/3
Find the zeros of 3x^2-25x+8=0
The zeros of 3x^2-25x+8=0 are x=8,x= 1/3