What are the solutions to the equation (2x+1)(x+8)=0 ?

The solutions to the equation (2x+1)(x+8)=0 are x=-1/2 ,x=-8

Find the zeros of (2x+1)(x+8)=0

The zeros of (2x+1)(x+8)=0 are x=-1/2 ,x=-8

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(2 x + 1) (x + 8) = 0

x = - \frac{1}{2}, x = - 8

Decimal Notation

x = - 0.5, x = - 8

Solution steps

(2 x + 1) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x + 8 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 8

3 x^{2} - 18 = - 6

9 y^{2} - 90 y + 8 = 0

- \frac{1}{5} x^{2} + 4 x + 1

x, x^{2} + y^{2} + z = 0

1 = 9 - x^{2}

What are the solutions to the equation (2x+1)(x+8)=0 ?
The solutions to the equation (2x+1)(x+8)=0 are x=-1/2 ,x=-8
Find the zeros of (2x+1)(x+8)=0
The zeros of (2x+1)(x+8)=0 are x=-1/2 ,x=-8