What are the solutions to the equation (x)(x-5)=234 ?

The solutions to the equation (x)(x-5)=234 are x=18,x=-13

Find the zeros of (x)(x-5)=234

The zeros of (x)(x-5)=234 are x=18,x=-13

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(x) (x - 5) = 234

x = 18, x = - 13

Solution steps

(x) (x - 5) = 234

Expand

(x) (x - 5) : x^{2} - 5 x

x^{2} - 5 x = 234

Move

234

to the left side

x^{2} - 5 x - 234 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 234 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 234) = 31

x_{1, 2} = \frac{- ( - 5 ) \pm 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 31}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 31}{2 \cdot 1}

x = \frac{- ( - 5 ) + 31}{2 \cdot 1} : 18

x = \frac{- ( - 5 ) - 31}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 18, x = - 13

13500 x^{2} + 52000000 x + 33000 = 0

x, (\frac{2 x - y}{2})^{2} + (\frac{y + 3 x}{3})^{2} = 1

(3 x + 2) (x - 5) = 0

x^{2} - 4 x = x - 4

6 t^{2} + 14 t - 6 = 0

What are the solutions to the equation (x)(x-5)=234 ?
The solutions to the equation (x)(x-5)=234 are x=18,x=-13
Find the zeros of (x)(x-5)=234
The zeros of (x)(x-5)=234 are x=18,x=-13