What are the solutions to the equation 9x^2-5x+4=0 ?

The solutions to the equation 9x^2-5x+4=0 are x= 5/18+i(sqrt(119))/(18),x= 5/18-i(sqrt(119))/(18)

Find the zeros of 9x^2-5x+4=0

The zeros of 9x^2-5x+4=0 are x= 5/18+i(sqrt(119))/(18),x= 5/18-i(sqrt(119))/(18)

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9 x^{2} - 5 x + 4 = 0

x = \frac{5}{18} + i \frac{119}{18}, x = \frac{5}{18} - i \frac{119}{18}

Solution steps

9 x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

Simplify

(- 5)^{2} - 4 \cdot 9 \cdot 4 : 119 i

x_{1, 2} = \frac{- ( - 5 ) \pm 119 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 119 i}{2 \cdot 9}, x_{2} = \frac{- ( - 5 ) - 119 i}{2 \cdot 9}

x = \frac{- ( - 5 ) + 119 i}{2 \cdot 9} : \frac{5}{18} + i \frac{119}{18}

x = \frac{- ( - 5 ) - 119 i}{2 \cdot 9} : \frac{5}{18} - i \frac{119}{18}

The solutions to the quadratic equation are:

x = \frac{5}{18} + i \frac{119}{18}, x = \frac{5}{18} - i \frac{119}{18}

- 2 - 5 c^{2} = - 92

c^{2} = - 10 c

x^{2} = 1 - 2 x

(x + 4) (x + 3) = 6

20 = \frac{n ( n - 3 )}{2}

What are the solutions to the equation 9x^2-5x+4=0 ?
The solutions to the equation 9x^2-5x+4=0 are x= 5/18+i(sqrt(119))/(18),x= 5/18-i(sqrt(119))/(18)
Find the zeros of 9x^2-5x+4=0
The zeros of 9x^2-5x+4=0 are x= 5/18+i(sqrt(119))/(18),x= 5/18-i(sqrt(119))/(18)