What are the solutions to the equation 3c^2-13c+4=-4 ?

The solutions to the equation 3c^2-13c+4=-4 are c=(13+sqrt(73))/6 ,c=(13-sqrt(73))/6

Find the zeros of 3c^2-13c+4=-4

The zeros of 3c^2-13c+4=-4 are c=(13+sqrt(73))/6 ,c=(13-sqrt(73))/6

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3 c^{2} - 13 c + 4 = - 4

c = \frac{13 + 73}{6}, c = \frac{13 - 73}{6}

Decimal Notation

c = 3.59066 \dots, c = 0.74266 \dots

Solution steps

3 c^{2} - 13 c + 4 = - 4

Move

4

to the left side

3 c^{2} - 13 c + 8 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

(- 13)^{2} - 4 \cdot 3 \cdot 8 = 73

c_{1, 2} = \frac{- ( - 13 ) \pm 73}{2 \cdot 3}

Separate the solutions

c_{1} = \frac{- ( - 13 ) + 73}{2 \cdot 3}, c_{2} = \frac{- ( - 13 ) - 73}{2 \cdot 3}

c = \frac{- ( - 13 ) + 73}{2 \cdot 3} : \frac{13 + 73}{6}

c = \frac{- ( - 13 ) - 73}{2 \cdot 3} : \frac{13 - 73}{6}

The solutions to the quadratic equation are:

c = \frac{13 + 73}{6}, c = \frac{13 - 73}{6}

y, x^{3} y^{2} = x^{2} + y^{2}

x^{2} + 2 x - 9 = 15

- 1 + \frac{( 60 - x ) ^{2}}{1200} = 0, x

3 x^{2} - 100 x + 460 = 0

(x - 6)^{2} = 19

What are the solutions to the equation 3c^2-13c+4=-4 ?
The solutions to the equation 3c^2-13c+4=-4 are c=(13+sqrt(73))/6 ,c=(13-sqrt(73))/6
Find the zeros of 3c^2-13c+4=-4
The zeros of 3c^2-13c+4=-4 are c=(13+sqrt(73))/6 ,c=(13-sqrt(73))/6