What are the solutions to the equation completesquare x^2+4x=1 ?

The solutions to the equation completesquare x^2+4x=1 are x=sqrt(5)-2,x=-sqrt(5)-2

Find the zeros of completesquare x^2+4x=1

The zeros of completesquare x^2+4x=1 are x=sqrt(5)-2,x=-sqrt(5)-2

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x^{2} + 4 x = 1

x = 5 - 2, x = - 5 - 2

Decimal Notation

x = 0.23606 \dots, x = - 4.23606 \dots

Solution steps

x^{2} + 4 x = 1

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = 5

For

the solutions are

f (x) = a, - a

Solve

x + 2 = 5 : x = 5 - 2

Solve

x + 2 = - 5 : x = - 5 - 2

The solutions to the quadratic equation are:

x = 5 - 2, x = - 5 - 2

2 x + 5 x^{2} = 1

(x + 3)^{2} = 3 (2 x + 3)

11.2 x^{2} = 392

3 x^{2} - 14 x - 14 = 0

x^{2} + x - 2 = 0

What are the solutions to the equation completesquare x^2+4x=1 ?
The solutions to the equation completesquare x^2+4x=1 are x=sqrt(5)-2,x=-sqrt(5)-2
Find the zeros of completesquare x^2+4x=1
The zeros of completesquare x^2+4x=1 are x=sqrt(5)-2,x=-sqrt(5)-2