What are the solutions to the equation l*(l-7)=260 ?

The solutions to the equation l*(l-7)=260 are l=20,l=-13

Find the zeros of l*(l-7)=260

The zeros of l*(l-7)=260 are l=20,l=-13

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l \cdot (l - 7) = 260

l = 20, l = - 13

Solution steps

l (l - 7) = 260

Expand

l (l - 7) : l^{2} - 7 l

l^{2} - 7 l = 260

Move

260

to the left side

l^{2} - 7 l - 260 = 0

Solve with the quadratic formula

l_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 260 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 260) = 33

l_{1, 2} = \frac{- ( - 7 ) \pm 33}{2 \cdot 1}

Separate the solutions

l_{1} = \frac{- ( - 7 ) + 33}{2 \cdot 1}, l_{2} = \frac{- ( - 7 ) - 33}{2 \cdot 1}

l = \frac{- ( - 7 ) + 33}{2 \cdot 1} : 20

l = \frac{- ( - 7 ) - 33}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

l = 20, l = - 13

- 6.5 x^{2} + 390 x - 2000 = 0

(- a + b + c - d) x^{2} + (a + 2 b + 2 c + (- d)) x + 2 d = 0

6 w^{2} - 18 w = 0

- 13 = 7 - 5 m^{2}

(2 x + 1)^{2} = 16

What are the solutions to the equation l*(l-7)=260 ?
The solutions to the equation l*(l-7)=260 are l=20,l=-13
Find the zeros of l*(l-7)=260
The zeros of l*(l-7)=260 are l=20,l=-13