What are the solutions to the equation (x-5)^2=25-9x ?

The solutions to the equation (x-5)^2=25-9x are x=1,x=0

Find the zeros of (x-5)^2=25-9x

The zeros of (x-5)^2=25-9x are x=1,x=0

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(x - 5)^{2} = 25 - 9 x

x = 1, x = 0

Solution steps

(x - 5)^{2} = 25 - 9 x

Expand

(x - 5)^{2} : x^{2} - 10 x + 25

x^{2} - 10 x + 25 = 25 - 9 x

Move

9 x

to the left side

x^{2} - x + 25 = 25

Move

25

to the left side

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

x, \frac{x ^{2}}{3} + 3 y^{2} = - 3 + 3

320 - 320 x - x^{2} = 0

3 x^{2} - 8 x = - x^{2}

5 x^{2} - 3 x^{2} = 8

10 x^{2} - 10 x + 9 = 2 x^{2} + 7 x

What are the solutions to the equation (x-5)^2=25-9x ?
The solutions to the equation (x-5)^2=25-9x are x=1,x=0
Find the zeros of (x-5)^2=25-9x
The zeros of (x-5)^2=25-9x are x=1,x=0