What are the solutions to the equation 5p^2-p-44=0 ?

The solutions to the equation 5p^2-p-44=0 are p=(1+sqrt(881))/(10),p=(1-sqrt(881))/(10)

Find the zeros of 5p^2-p-44=0

The zeros of 5p^2-p-44=0 are p=(1+sqrt(881))/(10),p=(1-sqrt(881))/(10)

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5 p^{2} - p - 44 = 0

p = \frac{1 + 881}{10}, p = \frac{1 - 881}{10}

Decimal Notation

p = 3.06816 \dots, p = - 2.86816 \dots

Solution steps

5 p^{2} - p - 44 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 44 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 44) = 881

p_{1, 2} = \frac{- ( - 1 ) \pm 881}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- ( - 1 ) + 881}{2 \cdot 5}, p_{2} = \frac{- ( - 1 ) - 881}{2 \cdot 5}

p = \frac{- ( - 1 ) + 881}{2 \cdot 5} : \frac{1 + 881}{10}

p = \frac{- ( - 1 ) - 881}{2 \cdot 5} : \frac{1 - 881}{10}

The solutions to the quadratic equation are:

p = \frac{1 + 881}{10}, p = \frac{1 - 881}{10}

16 v^{2} - 40 v + 31 = 6

5 x^{2} + 4 x = - 4

x^{2} + 7 x + 10

x^{2} + 2 x = 0

λ^{2} + λ - 6 (1) = 0

What are the solutions to the equation 5p^2-p-44=0 ?
The solutions to the equation 5p^2-p-44=0 are p=(1+sqrt(881))/(10),p=(1-sqrt(881))/(10)
Find the zeros of 5p^2-p-44=0
The zeros of 5p^2-p-44=0 are p=(1+sqrt(881))/(10),p=(1-sqrt(881))/(10)