What are the solutions to the equation (2s^2+8s+16)=0 ?

The solutions to the equation (2s^2+8s+16)=0 are s=-2+2i,s=-2-2i

Find the zeros of (2s^2+8s+16)=0

The zeros of (2s^2+8s+16)=0 are s=-2+2i,s=-2-2i

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(2 s^{2} + 8 s + 16) = 0

s = - 2 + 2 i, s = - 2 - 2 i

Solution steps

(2 s^{2} + 8 s + 16) = 0

Refine

2 s^{2} + 8 s + 16 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 16}{2 \cdot 2}

Simplify

8^{2} - 4 \cdot 2 \cdot 16 : 8 i

s_{1, 2} = \frac{- 8 \pm 8 i}{2 \cdot 2}

Separate the solutions

s_{1} = \frac{- 8 + 8 i}{2 \cdot 2}, s_{2} = \frac{- 8 - 8 i}{2 \cdot 2}

s = \frac{- 8 + 8 i}{2 \cdot 2} : - 2 + 2 i

s = \frac{- 8 - 8 i}{2 \cdot 2} : - 2 - 2 i

The solutions to the quadratic equation are:

s = - 2 + 2 i, s = - 2 - 2 i

2.7 \cdot 1 0^{- 9} \cdot x^{2} - 16 \cdot 1 0^{- 5} \cdot x + 0.5 = 0

2 x^{2} = 18 x - 16

2 x^{2} - x = + 21

- 3 x^{2} + 6 x - 2 = 0.75

x = 0.008 (1 - \frac{( 4 - 390 \cdot x )}{( - 8 )})^{2}

What are the solutions to the equation (2s^2+8s+16)=0 ?
The solutions to the equation (2s^2+8s+16)=0 are s=-2+2i,s=-2-2i
Find the zeros of (2s^2+8s+16)=0
The zeros of (2s^2+8s+16)=0 are s=-2+2i,s=-2-2i