What are the solutions to the equation 28090=25000(1+r/(100))^2 ?

The solutions to the equation 28090=25000(1+r/(100))^2 are r=6,r=-206

Find the zeros of 28090=25000(1+r/(100))^2

The zeros of 28090=25000(1+r/(100))^2 are r=6,r=-206

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28090 = 25000 (1 + \frac{r}{100})^{2}

r = 6, r = - 206

Solution steps

28090 = 25000 (1 + \frac{r}{100})^{2}

Switch sides

25000 (1 + \frac{r}{100})^{2} = 28090

Divide both sides by

25000

(1 + \frac{r}{100})^{2} = \frac{2809}{2500}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 + \frac{r}{100} = \frac{2809}{2500} : r = 6

Solve

1 + \frac{r}{100} = - \frac{2809}{2500} : r = - 206

The solutions to the quadratic equation are:

r = 6, r = - 206

(x + 4)^{2} = 361

3 x^{2} + 5 = 16 x

4 x^{2} + 1 = 8 x - 2

200 - 2 x = 100 + 0.2 \cdot x^{2}

15 x^{2} + 35 x = 0

What are the solutions to the equation 28090=25000(1+r/(100))^2 ?
The solutions to the equation 28090=25000(1+r/(100))^2 are r=6,r=-206
Find the zeros of 28090=25000(1+r/(100))^2
The zeros of 28090=25000(1+r/(100))^2 are r=6,r=-206