What are the solutions to the equation 2x^2-10x+15=0 ?

The solutions to the equation 2x^2-10x+15=0 are x= 5/2+i(sqrt(5))/2 ,x= 5/2-i(sqrt(5))/2

Find the zeros of 2x^2-10x+15=0

The zeros of 2x^2-10x+15=0 are x= 5/2+i(sqrt(5))/2 ,x= 5/2-i(sqrt(5))/2

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2 x^{2} - 10 x + 15 = 0

x = \frac{5}{2} + i \frac{5}{2}, x = \frac{5}{2} - i \frac{5}{2}

Solution steps

2 x^{2} - 10 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

Simplify

(- 10)^{2} - 4 \cdot 2 \cdot 15 : 25 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 5 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 5 i}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 5 i}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 5 i}{2 \cdot 2} : \frac{5}{2} + i \frac{5}{2}

x = \frac{- ( - 10 ) - 2 5 i}{2 \cdot 2} : \frac{5}{2} - i \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{5}{2}, x = \frac{5}{2} - i \frac{5}{2}

x^{2} + 6 x - 7 = 0

x, (x - a)^{2} + y^{2} = b

x, y^{3} - 2 x^{2} = 1388

(m^{2} - n^{2}) x^{2} - 4 mn x = m^{2} - n^{2}

\frac{2 x ^{2} + 7 x - 21}{16} - \frac{x ^{2} - 3}{4} = x

What are the solutions to the equation 2x^2-10x+15=0 ?
The solutions to the equation 2x^2-10x+15=0 are x= 5/2+i(sqrt(5))/2 ,x= 5/2-i(sqrt(5))/2
Find the zeros of 2x^2-10x+15=0
The zeros of 2x^2-10x+15=0 are x= 5/2+i(sqrt(5))/2 ,x= 5/2-i(sqrt(5))/2