What are the solutions to the equation -w^2+6w+72=0 ?

The solutions to the equation -w^2+6w+72=0 are w=-6,w=12

Find the zeros of -w^2+6w+72=0

The zeros of -w^2+6w+72=0 are w=-6,w=12

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- w^{2} + 6 w + 72 = 0

w = - 6, w = 12

Solution steps

- w^{2} + 6 w + 72 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 72}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 72 = 18

w_{1, 2} = \frac{- 6 \pm 18}{2 ( - 1 )}

Separate the solutions

w_{1} = \frac{- 6 + 18}{2 ( - 1 )}, w_{2} = \frac{- 6 - 18}{2 ( - 1 )}

w = \frac{- 6 + 18}{2 ( - 1 )} : - 6

w = \frac{- 6 - 18}{2 ( - 1 )} : 12

The solutions to the quadratic equation are:

w = - 6, w = 12

n C^{2} = 15

x^{2} - 12 = 13

x, x^{2} - 3 x y + 5 = 0

- 4 x^{2} - 80 = 0

0.0813600000000 \dots + 0.2431900000000 \dots \cdot x + 0.3564800000000 \dots \cdot x^{2} = 0

What are the solutions to the equation -w^2+6w+72=0 ?
The solutions to the equation -w^2+6w+72=0 are w=-6,w=12
Find the zeros of -w^2+6w+72=0
The zeros of -w^2+6w+72=0 are w=-6,w=12