What are the solutions to the equation sqrt(3)x^2+1=0 ?

The solutions to the equation sqrt(3)x^2+1=0 are x=sqrt(-1/(\sqrt{3))},x=-sqrt(-1/(\sqrt{3))}

Find the zeros of sqrt(3)x^2+1=0

The zeros of sqrt(3)x^2+1=0 are x=sqrt(-1/(\sqrt{3))},x=-sqrt(-1/(\sqrt{3))}

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3 x^{2} + 1 = 0

x = - \frac{1}{3}, x = - - \frac{1}{3}

Solution steps

3 x^{2} + 1 = 0

Move

1

to the right side

3 x^{2} = - 1

Divide both sides by

3

x^{2} = - \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{3}, x = - - \frac{1}{3}

- 3 x^{2} + 24 x - 50

7 x^{2} + 2 x - 9 = 0

(a - \frac{2}{3})^{2} = 13

x^{2} + 196 x - 710 = 0

x^{2} + 3 = x + 3

What are the solutions to the equation sqrt(3)x^2+1=0 ?
The solutions to the equation sqrt(3)x^2+1=0 are x=sqrt(-1/(\sqrt{3))},x=-sqrt(-1/(\sqrt{3))}
Find the zeros of sqrt(3)x^2+1=0
The zeros of sqrt(3)x^2+1=0 are x=sqrt(-1/(\sqrt{3))},x=-sqrt(-1/(\sqrt{3))}