What is x(3x+2)<= (x+2)^2 ?

The solution to x(3x+2)<= (x+2)^2 is -1<= x<= 2

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x(3x+2)<= (x+2)^2

x (3 x + 2) \leq (x + 2)^{2}

- 1 \leq x \leq 2

Interval Notation

[- 1, 2]

Solution steps

x (3 x + 2) \leq (x + 2)^{2}

Rewrite in standard form

x^{2} - x - 2 \leq 0

Factor

x^{2} - x - 2 : (x + 1) (x - 2)

(x + 1) (x - 2) \leq 0

Identify the intervals

- 1 \leq x \leq 2

f = - 4 + 4

- (\frac{2}{5})^{4}

\frac{a ^{23} - b ^{22}}{( a ^{3} + b ^{2} ) ^{2}} + 1

3 x - 2 = 7 - 6 x

\frac{3}{12}