What are the solutions to the equation x^2+12^2=16^2 ?

The solutions to the equation x^2+12^2=16^2 are x=4sqrt(7),x=-4sqrt(7)

Find the zeros of x^2+12^2=16^2

The zeros of x^2+12^2=16^2 are x=4sqrt(7),x=-4sqrt(7)

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x^{2} + 1 2^{2} = 1 6^{2}

x = 47, x = - 47

Decimal Notation

x = 10.58300 \dots, x = - 10.58300 \dots

Solution steps

x^{2} + 1 2^{2} = 1 6^{2}

Move

1 2^{2}

to the right side

x^{2} = 112

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 112, x = - 112

112 = 47

- 112 = - 47

x = 47, x = - 47

z^{2} + 2 z + 17 = 0

x, x^{2} + y^{2} + z^{2} = 4 x

x, x^{2} + y^{2} - z = 0

5 y^{2} - 12 y + 2 = - 3 y

s^{2} + 5 s + 5 = 0

What are the solutions to the equation x^2+12^2=16^2 ?
The solutions to the equation x^2+12^2=16^2 are x=4sqrt(7),x=-4sqrt(7)
Find the zeros of x^2+12^2=16^2
The zeros of x^2+12^2=16^2 are x=4sqrt(7),x=-4sqrt(7)