What are the solutions to the equation y^2-15y+56=0 ?

The solutions to the equation y^2-15y+56=0 are y=8,y=7

Find the zeros of y^2-15y+56=0

The zeros of y^2-15y+56=0 are y=8,y=7

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y^{2} - 15 y + 56 = 0

y = 8, y = 7

Solution steps

y^{2} - 15 y + 56 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 56 = 1

y_{1, 2} = \frac{- ( - 15 ) \pm 1}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 15 ) + 1}{2 \cdot 1}, y_{2} = \frac{- ( - 15 ) - 1}{2 \cdot 1}

y = \frac{- ( - 15 ) + 1}{2 \cdot 1} : 8

y = \frac{- ( - 15 ) - 1}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

y = 8, y = 7

- 75 x^{2} - 45 x - 6 = 0

x - 12 = (x + 4) (x + 11)

- 2 (x + x^{2}) = 3

2 x^{2} + 6 x = 5

(r + 2)^{2} = 0

What are the solutions to the equation y^2-15y+56=0 ?
The solutions to the equation y^2-15y+56=0 are y=8,y=7
Find the zeros of y^2-15y+56=0
The zeros of y^2-15y+56=0 are y=8,y=7