What are the solutions to the equation (x+4)^2+7(x+4)+10=0 ?

The solutions to the equation (x+4)^2+7(x+4)+10=0 are x=-6,x=-9

Find the zeros of (x+4)^2+7(x+4)+10=0

The zeros of (x+4)^2+7(x+4)+10=0 are x=-6,x=-9

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(x + 4)^{2} + 7 (x + 4) + 10 = 0

x = - 6, x = - 9

Solution steps

(x + 4)^{2} + 7 (x + 4) + 10 = 0

Expand

(x + 4)^{2} + 7 (x + 4) + 10 : x^{2} + 15 x + 54

x^{2} + 15 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 54 = 3

x_{1, 2} = \frac{- 15 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 3}{2 \cdot 1}, x_{2} = \frac{- 15 - 3}{2 \cdot 1}

x = \frac{- 15 + 3}{2 \cdot 1} : - 6

x = \frac{- 15 - 3}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 6, x = - 9

x^{2} - 18 x + 73 = 0

25 x^{2} - 15 x = 0

x^{2} - 10 x + 15 = 0

- x^{2} + 11 x - 28 = 0

2 x^{2} - 12 x + 6 = 0

What are the solutions to the equation (x+4)^2+7(x+4)+10=0 ?
The solutions to the equation (x+4)^2+7(x+4)+10=0 are x=-6,x=-9
Find the zeros of (x+4)^2+7(x+4)+10=0
The zeros of (x+4)^2+7(x+4)+10=0 are x=-6,x=-9