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What are the solutions to the equation ((sqrt(35))/6)^2+y^2=1 ?
The solutions to the equation ((sqrt(35))/6)^2+y^2=1 are y= 1/6 ,y=-1/6Find the zeros of ((sqrt(35))/6)^2+y^2=1
The zeros of ((sqrt(35))/6)^2+y^2=1 are y= 1/6 ,y=-1/6